β
Tm = 81.5 + 16.6 (log10[na+]) + 0.41 (%G+C) 675/n [Na+] monovalent cations ( [Na+] = [K+] ) n =primer base Tm = 81.5 + 16.6 (log10[0.05]) + 0.41 (60) 675/22 = 81.5 + 16.6 ( 1.30) + 24.60 30.68 = 53.84 C
λ λ
λ